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# Unbelievable Math Trick

15 replies to this topic

### #1 boopme

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Posted 22 March 2007 - 02:59 PM

Here is a math trick so unbelievable that it will wow you.

1. Grab a calculator.
2. Key in the first three digits of your phone number
(NOT the area code)
3. Multiply by 80
5. Multiply by 250
8. Subtract 250
9. Divide number by 2
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### #2 nn23

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Posted 22 March 2007 - 03:04 PM

DARN IT! i want a calculater! i shall have to do it manually

### #3 ddeerrff

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Posted 22 March 2007 - 03:15 PM

If you let
abc = first 3 digits
defg = last 4 digits

Then simplify.......

The answer becomes 10,000*abc + defg which will yield the original phone number.
Derfram
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### #4 nn23

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Posted 22 March 2007 - 03:21 PM

the divisions stumped me oh wellll

### #5 ddeerrff

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Posted 22 March 2007 - 03:21 PM

{[(abc * 80) + 1) * 250] + 2*defg - 250}/2 ->

(20,000abc + 250 + 2defg - 250)/2 ->

(20,000abc +2defg)/2 ->

10,000abc +defg
Derfram
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### #6 JohnWho

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Posted 22 March 2007 - 03:41 PM

You know,

you can save a lot of steps

by simply keying in the last 7 digits of your phone number.

However,

try as I may,

I can't get my calculator to dial the number!

Maybe I should have used the calculator function on my cell phone?

I know you think you understand what you thought I said,
but I'm not sure you realize that what you heard is not what I meant!

Feed me some spyware!

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Posted 22 March 2007 - 04:25 PM

Windows/run/calc

Very neat.

### #8 tink536

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Posted 23 March 2007 - 07:15 AM

That's pretty cool boopme.

I search for Sjogrens Syndrome Foundation...Who will you search for?

### #9 Mr Alpha

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Posted 23 March 2007 - 10:29 AM

Here is a classic:
• Let x and y be equal, non-zero quantities
x = y
• Add x to both sides
2x = x + y
• Take 2y from both sides
2x − 2y = x − y
• Factor out a two on the left side
2(x − y) = x − y
• Divide out (x − y)
2 = 1

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### #10 ddeerrff

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Posted 23 March 2007 - 11:17 AM

I have the answer, but will wait.....

Edited by ddeerrff, 23 March 2007 - 11:20 AM.

Derfram
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### #11 TMacK

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Posted 23 March 2007 - 11:34 AM

That was fun boopme!
Will not attempt the second one but admire those who do!! (Math wasn't my best subject in high school )
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Reflect, repent, and reboot.
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### #12 Darthy

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Posted 23 March 2007 - 05:09 PM

I have the answer, but will wait.....

{[(abc * 80) + 1) * 250] + 2*defg - 250}/2 ->

(20,000abc + 250 + 2defg - 250)/2 ->

(20,000abc +2defg)/2 ->

10,000abc +defg

Very well ddeerrff.

Edited by Darthy, 23 March 2007 - 05:13 PM.

Εν οίδα οτι ουδέν οίδα - Socrates
Thanks John

### #13 JohnWho

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Posted 23 March 2007 - 05:56 PM

Here is a classic:

• Let x and y be equal, non-zero quantities
x = y

See,

I'm having a problem right there -

"x" refuses to be "y" .

Something about a sexual identy crisis.

I know you think you understand what you thought I said,
but I'm not sure you realize that what you heard is not what I meant!

### #14 ddeerrff

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Posted 23 March 2007 - 07:33 PM

Darthy, I meant to Mr Alpha's post. It has something to do with dividing by zero.
Derfram
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### #15 Darthy

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Posted 23 March 2007 - 11:01 PM

Yes ddeerrff. Any real number divided by zero = infinite.
Infinite it's an amount that doesn't belong to real numbers, because R=]-infinite;+infinite[ and when Mr Alpha divides the two members of the equation 2(x-y) = x-y by x-y is divided 0 by 0 what makes this divisions undetermined.
If x = y, x-y = 0, so 2*0/0 = 0/0 what makes no sense in R, because 0/0 = undetermination.
Regards,
Darthy

Edited by Darthy, 23 March 2007 - 11:09 PM.

Εν οίδα οτι ουδέν οίδα - Socrates
Thanks John

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