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Unbelievable Math Trick


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15 replies to this topic

#1 boopme

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Posted 22 March 2007 - 02:59 PM

Here is a math trick so unbelievable that it will wow you.


1. Grab a calculator.
(you won't be able to do this one in your head)
2. Key in the first three digits of your phone number
(NOT the area code)
3. Multiply by 80
4. Add 1
5. Multiply by 250
6. Add the last 4 digits of your phone number
7. Add the last 4 digits of your phone number again.
8. Subtract 250
9. Divide number by 2
Do you recognize the answer?
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#2 nn23

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Posted 22 March 2007 - 03:04 PM

DARN IT! i want a calculater! i shall have to do it manually :thumbsup:

#3 ddeerrff

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Posted 22 March 2007 - 03:15 PM

If you let
abc = first 3 digits
defg = last 4 digits

Then simplify.......

The answer becomes 10,000*abc + defg which will yield the original phone number.
Derfram
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#4 nn23

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Posted 22 March 2007 - 03:21 PM

the divisions stumped me :flowers: oh wellll :thumbsup: :trumpet:

#5 ddeerrff

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Posted 22 March 2007 - 03:21 PM

{[(abc * 80) + 1) * 250] + 2*defg - 250}/2 ->

(20,000abc + 250 + 2defg - 250)/2 ->

(20,000abc +2defg)/2 ->

10,000abc +defg
Derfram
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#6 JohnWho

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Posted 22 March 2007 - 03:41 PM

You know,

you can save a lot of steps

by simply keying in the last 7 digits of your phone number.

However,

try as I may,

I can't get my calculator to dial the number!

Maybe I should have used the calculator function on my cell phone?

:thumbsup:


I know you think you understand what you thought I said,
but I'm not sure you realize that what you heard is not what I meant!


#7 cowsgonemadd3

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Posted 22 March 2007 - 04:25 PM

Windows/run/calc

Very neat.

#8 tink536

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Posted 23 March 2007 - 07:15 AM

That's pretty cool boopme. :thumbsup:

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#9 Mr Alpha

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Posted 23 March 2007 - 10:29 AM

Here is a classic:
  • Let x and y be equal, non-zero quantities
    x = y
  • Add x to both sides
    2x = x + y
  • Take 2y from both sides
    2x − 2y = x − y
  • Factor out a two on the left side
    2(x − y) = x − y
  • Divide out (x − y)
    2 = 1

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#10 ddeerrff

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Posted 23 March 2007 - 11:17 AM

I have the answer, but will wait.....

Edited by ddeerrff, 23 March 2007 - 11:20 AM.

Derfram
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#11 TMacK

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Posted 23 March 2007 - 11:34 AM

That was fun boopme!
Will not attempt the second one but admire those who do!! (Math wasn't my best subject in high school :thumbsup: )
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Reflect, repent, and reboot.
Order shall return.

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#12 Darthy

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Posted 23 March 2007 - 05:09 PM

I have the answer, but will wait.....

I have the answer too. :thumbsup:

{[(abc * 80) + 1) * 250] + 2*defg - 250}/2 ->

(20,000abc + 250 + 2defg - 250)/2 ->

(20,000abc +2defg)/2 ->

10,000abc +defg

Very well ddeerrff.

Edited by Darthy, 23 March 2007 - 05:13 PM.

Εν οίδα οτι ουδέν οίδα - Socrates
Thanks John

#13 JohnWho

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Posted 23 March 2007 - 05:56 PM

Here is a classic:

  • Let x and y be equal, non-zero quantities
    x = y

See,

I'm having a problem right there -

"x" refuses to be "y" .

Something about a sexual identy crisis.

:thumbsup:


I know you think you understand what you thought I said,
but I'm not sure you realize that what you heard is not what I meant!


#14 ddeerrff

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Posted 23 March 2007 - 07:33 PM

Darthy, I meant to Mr Alpha's post. It has something to do with dividing by zero.
Derfram
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#15 Darthy

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Posted 23 March 2007 - 11:01 PM

Yes ddeerrff. Any real number divided by zero = infinite.
Infinite it's an amount that doesn't belong to real numbers, because R=]-infinite;+infinite[ and when Mr Alpha divides the two members of the equation 2(x-y) = x-y by x-y is divided 0 by 0 what makes this divisions undetermined.
If x = y, x-y = 0, so 2*0/0 = 0/0 what makes no sense in R, because 0/0 = undetermination.
Regards,
Darthy

Edited by Darthy, 23 March 2007 - 11:09 PM.

Εν οίδα οτι ουδέν οίδα - Socrates
Thanks John




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