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Memory "Number of Component" - Is more better?


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#1 RECACER

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Posted 29 July 2015 - 02:26 PM

Not sure how to ask this so there it goes...

 

 

Trying to narrow down the definition of Number of Component when it refers to memory sticks.  Based on the following information, would either perform better than the other...

 

 

*Both unbuffered 2gb DDR3.  All other specs, except for "Number of Component", are identical.

Organized as two ranks of 256Mx64 (2GB) high-speed memory array. Modules use sixteen 128Mx8 (2GB) 78-ball BGA packaged devices.

Organized as one rank of 256Mx64 (2GB) high-speed memory array. Modules use eight 256Mx8 (2GB) 78-ball BGA packaged devices.

 

 

Comes from same manufacture.

 

 

If more information is needed, I will happily supply (if I can).

 

Thanks in advance.



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#2 YeahBleeping

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Posted 29 July 2015 - 02:50 PM

Here you go

 

9 vs 18 chips



#3 RECACER

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Posted 29 July 2015 - 03:51 PM

Thanks, although I'm not sure how that answers my question. 

 

In regards to performance, is there a benefit of having a 2gb stick with 2 ranks/16 modules (chips) vs 1 rank/8 modules (chips)?



#4 YeahBleeping

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Posted 30 July 2015 - 07:16 AM

I don't really think you would see a performance difference but some architectures are 'not compatible' with some motherboards.  So it really comes down to what will work in the system.  If both of those types of chips will work than you would probably not 'see' any kind of a performance change in either one.



#5 RECACER

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Posted 30 July 2015 - 04:03 PM

Thanks again!

 

I was worried about that.  I think I'll stick with the same exact sticks that are currently in my XPS.

 

Take care.






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