Jump to content


Register a free account to unlock additional features at BleepingComputer.com
Welcome to BleepingComputer, a free community where people like yourself come together to discuss and learn how to use their computers. Using the site is easy and fun. As a guest, you can browse and view the various discussions in the forums, but can not create a new topic or reply to an existing one unless you are logged in. Other benefits of registering an account are subscribing to topics and forums, creating a blog, and having no ads shown anywhere on the site.

Click here to Register a free account now! or read our Welcome Guide to learn how to use this site.


Headphones only work in USB sound card

  • Please log in to reply
1 reply to this topic

#1 bdnh85


  • Members
  • 38 posts
  • Local time:01:15 AM

Posted 30 January 2012 - 06:13 PM

I need help, I'm running Windows Vista and my problem is I bought a USB sound card for my computer to run my police scanner. I tried plugging my headphones into the headphone jack but go no sound. I tried the back of my PC tower and got the same problem. It will only work when I plug it into USB sound card. Can anyone help me getting my headphones to work without disturbing the scanner since its online to host a feed.

Thank You

BC AdBot (Login to Remove)


#2 Capn Easy

Capn Easy

  • Members
  • 597 posts
  • Location:New Jersey
  • Local time:02:15 AM

Posted 30 January 2012 - 11:28 PM

I occasionally use a USB sound card (in my case, to get an optical output) on my computer, running XP. Whenever I connect the USB sound card the onboard audio is cut off. I can toggle back and forth between the two outputs using the Control Panel, but it doesn't give me the option to use both outputs simultaneously. I think this is normal operation.

It sounds like you want to run one audio stream to the USB card and a second audio stream to the onboard audio. I don't know if there is any way to force the computer to use two different active audio outputs.

If anyone knows of a way to do this I'd like to know, too.

0 user(s) are reading this topic

0 members, 0 guests, 0 anonymous users