Posted 21 July 2010 - 10:04 AM
Hello and welcome to Bleepingcomputer.
To answer your question about integrated graphics cards over heating, the answer to that question is yes.
The reason is anything that processes requires a great many transistors to do the processing, the faster the transistors have to switch on and off to crunch the data being thrown at them, the more heat they produce in the process.
In order to draw (scan) a complete picture in pixels across the screen with high resolution graphics included, the video processor has to scan faster with more detail in each frame, this creates more heat in the process. If this heat builds up on the transistor network built into a processor of any type, the transistors either heat up and shut off or burn open.
In the case of burning open, this means the transistor has suffered permanent damage and will no longer work again.
Transistors built into todays electronics are integrated into an Integrated Circuit also called IC chip. There is no way to service such a chip, because the chips have microscopic circuitry built into them and the chips are sealed, so there would be no way to repair a burned transistor inside an IC chip because the chip would be damaged further if such an attempt was made.
So in this case the whole chip has to be replaced. Even this is not easy to accomplish, since the chips soldered connections to the motherboard are surface mount technology and very hard to accomplish without the use of a microscope and an ultra fine tipped 15 watt grounded soldering pencil and a very steady hand. One solder bridge between the leads on the chip could damage the new chip. ( A solder bridge is when a bead of solder joins two leads together, that are not meant to be connected.)
So now we get back to the questions you asked above.
Yes, the integrated graphics card can over heat.
Yes you can replace the chip, but most motherboards have the darned chip soldered to the motherboard. I wish they would start installing them into IC sockets rather than hard-wiring them to the circuit board.
Hope this helps answer your question.
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