BleepingComputer.com: Python Array Copying

Hello.

I'm having some trouble with arrays in Python. From what I understand, when a statement such as the one below is used, the NewArray does not contain a copy of the OldArray, but any references to NewArray are simply redirected to OldArray.

NewArray = OldArray

This is demontrated:

Array = [1,1,1,1,1,1]
Arr2 = Array
Array[0] = 99
print Arr2

returns [99, 1, 1, 1, 1, 1]

I can work around this by doing such.

Array = [1,1,1,1,1,1]
Arr2 = Array[:]
Array[0] = 99
print Arr2

This doesn't work when I want to call a function that has an array as an argument.

def MakeMove(Board,Rows,Marker,Move):
	Board = Board[:]
	for i in range(0,Rows):
		i = (Rows-1)-i
		if Board[i][Move]==".":
			Board[i][Move] = Marker
			break
	return Board

(Function from a connect 4 game)

Normally, I would use this to actually change the board, in which case it works well.

However, when I want to test a potential new move using this function, it still alters the argument passed to it.

For instance:

TestBoard = MakeMove(TheBoard[:],Rows,Marker,Move)

TheBoard variable is changed.

Is there some way to avoid this?

Thanks,
The Panda

Try changing the variable names as shown in bold:

def MakeMove(Bord,Rows,Marker,Move):
Board = Bord[:]

Thanks, but I figured it out .

Quote

I tried changing the variable name yesterday, but it didn't work.

With Regards,
The Panda